Passing Multiple Values from Functions

by Anshoo Arora ON August 10, 2009 · Posted In All, QTP, VBScript · 3 comments

There are several ways to return multiple values from functions. In this topic, we’re going to look over the 5 most common techniques to pass 2 or more values from functions. The 5 techniques are:

  1. Returning variables in Global scope
  2. Returning a Collection
  3. Returning Arrays
  4. Using Concatenated Strings
  5. Passing through the use of ByRef

Returning variables in Global scope

This can be achieved by declaring the variables outside the scope of the function. Here, we don’t need to pass the values through the function; but we can simply manipulate them within the function’s scope. Please note that if the same string is declared within the function, it loses its global scope – as it becomes local to the function. These variables can come from a function library or from the test script as long as they are outside the scope of the calling method. Code snippet:

Dim intNumber_1: intNumber_1 = 40
Dim intNumber_2: intNumber_2 = 80
 
Public Sub PassValues
    intNumber_1 = intNumber_1/4
    intNumber_2 = intNumber_2/4
End Sub
 
PassValues
 
MsgBox "intNumber_1 = " & intNumber_1 &_
    vbLf & "intNumber_2 = " & intNumber_2
Demo

Use of Global Variables

Returning a Collection

Another way to pass multiple values from a function is through the using of creating and passing Collections. We can use a collection object to store multiple values as keys/items. Code snippet:

Public Function PassValues(ByVal Num_1, ByVal Num_2)
    Set oDict = CreateObject( "Scripting.Dictionary" )
 
    With oDict
        .Add "Num_1", Num_1/4
        .Add "Num_2", Num_2/2
    End With
 
    Set PassValues = oDict
End Function
 
Set colNumbers = PassValues(40,80)
 
MsgBox "intNumber_1 = " & colNumbers.Item("Num_1") &_
    vbLf & "intNumber_2 = " & colNumbers.Item("Num_2")
Demo

Use of Scripting.Dictionary

Returning Arrays

This is quite a common technique. Each element in the array stores a variable that is then passed through the function. Code snippet:

Public Function PassValues(ByVal Num_1, ByVal Num_2)
    Dim arrArray: ReDim arrArray(2)
 
    arrArray(0) = Num_1/4
    arrArray(1) = Num_2/2
 
    PassValues = arrArray
End Function
 
arrNew = PassValues(40,80)
 
MsgBox "intNumber_1 = " & arrNew(0) &_
    vbLf & "intNumber_2 = " & arrNew(1)
Demo

Use of Arrays

Concatenated Strings

I have seen the usage of this technique almost as frequently as the use of arrays. Here, two or more concatenated numbers/strings can be passed through the function with the help of a delimiter. Code snippet:

Public Function PassValues(ByVal Num_1, ByVal Num_2)
    Num_1 = Num_1/4
    Num_2 = Num_2/2
 
    PassValues = Num_1 & "," & Num_2
End Function
 
sNum = PassValues(40,80)
 
MsgBox "intNumber_1 = " & Split(sNum, ",")(0) &_
    vbLf & "intNumber_2 = " & Split(sNum, ",")(1)
Demo

Using Concatenated Strings

Note above that, concatenated string was passed, it must be broken by using one of the delimiting techniques (split, left, right etc.)

Using ByRef to Pass Multiple Values

Please refer to the article Passing Parameters ByRef and ByVal for a detailed explanation of this technique. It can be used to pass multiple values in the following manner:

Dim intNumber_1: intNumber_1 = 40
Dim intNumber_2: intNumber_2 = 80
 
Public Sub PassValues(ByRef Num_1, ByRef Num_2)
    Num_1 = Num_1/4
    Num_2 = Num_2/2
End Sub
 
PassValues intNumber_1, intNumber_2
 
MsgBox "intNumber_1 = " & intNumber_1 &_
    vbLf & "intNumber_2 = " & intNumber_2
Demo

Using ByRef

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{ 3 comments… read them below or add one }

Jena February 28, 2011 at 4:21 am

Hi Anshoo,
“Pssing Multiple Values from Functions” post is really helpful to me. This website with your effort is really worth reading. I would say its really a best website for QTP, I had ever browsed before.
Thank you so much for your contribution towards QTP prof.

Keep Blogging n Posting.
Cheers,

Reply

Shaphi November 13, 2009 at 10:41 am

Hi Anshoo Arora,
I am new to qtp and vbscript. please give me an easy way to understand the logic in the below code.
I googled for regexp and found this to find the intergers in an string.

sText = "qtp 123 qtp 154"

Set oRegExp = New RegExp
oRegExp.Pattern = "\d+"
oRegExp.Global = True
set colMatches = oRegExp.Execute (sText)

iThisItem = colMatches.count

for each sItem in colMatches
    sNewValue = sNewValue&" "&sItem  '
next

msgbox sNewValue

Please tell me the For each…loop. when “sNewValue = sItem& ” “&SNewValue” i get 154 123 and in the above code i am getting 123 154. How?
Thank you very much
Md shaphi

Reply

Anshoo Arora November 13, 2009 at 2:51 pm

Hi Staphi,

The code you have there uses the pattern: “\d+” which is used to match any occurence of a number within a given string. Thus, when the RegExp code you have in the post executes, it uses the “sText” string and matches any occurence within the string that is a number. Thus, you get the following output:

154 123

where, 154 is the first occurence of the match and 123 is the second. Similarly, if you would to match “any” alphabet, you can simply negate the “\d+” pattern by doing so: [^\d+]“. Example:

sText = "qtp 123 qtp 154"

Set oRegExp = New RegExp
oRegExp.Pattern = "[^\d]"
oRegExp.Global = True
set colMatches = oRegExp.Execute (sText)

iThisItem = colMatches.count

MsgBox iThisItem

for each sItem in colMatches
    sNewValue = sNewValue&" "&sItem  '
next

msgbox sNewValue

When the above code executes, you will have the following output: “qtp qtp”

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